(2x^2+3x-54)/(x^2-5x+6)=0

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Solution for (2x^2+3x-54)/(x^2-5x+6)=0 equation:


D( x )

x^2-(5*x)+6 = 0

x^2-(5*x)+6 = 0

x^2-(5*x)+6 = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

x in (-oo:2) U (2:3) U (3:+oo)

(2*x^2+3*x-54)/(x^2-(5*x)+6) = 0

(2*x^2+3*x-54)/(x^2-5*x+6) = 0

2*x^2+3*x-54 = 0

2*x^2+3*x-54 = 0

DELTA = 3^2-(-54*2*4)

DELTA = 441

DELTA > 0

x = (441^(1/2)-3)/(2*2) or x = (-441^(1/2)-3)/(2*2)

x = 9/2 or x = -6

(x+6)*(x-9/2) = 0

x^2-5*x+6 = 0

x^2-5*x+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

x = (1^(1/2)+5)/(1*2) or x = (5-1^(1/2))/(1*2)

x = 3 or x = 2

(x-2)*(x-3) = 0

((x+6)*(x-9/2))/((x-2)*(x-3)) = 0

( x+6 )

x+6 = 0 // - 6

x = -6

( x-9/2 )

x-9/2 = 0 // + 9/2

x = 9/2

x in { -6, 9/2 }

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